Question

What is the Cartesian form of `( -13 , (16pi)/6 )`?

Answer 1

`x=rcostheta`
`y=rsintheta`
`sin(16/6pi)=sqrt3/2`
`cos(16/6pi)=-1/2`
`(x,y)=(-13/2,-13sqrt3/2)`

Explanation:

Use the formula to calculate
By the definition