What is the Cartesian form of $(-15,(-pi)/4))$ ?

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Answer 1 · 2016-05-19T14:49:41

$x=(-15*sqrt2)/2$ and $y=(+15*sqrt2)/2$

The formulas to be used are

$x=r*cos theta$
$y=r*sin theta$

$x=-15*cos (-pi/4)=-15*(+sqrt2)/2=(-15*sqrt2)/2$

and

$y=-15*sin (-pi/4)=-15*(-sqrt2)/2=(+15*sqrt2)/2$

God bless....I hope the explanation is useful.

What is the Cartesian form of (-15,(-pi)/4))(-15,(-pi)/4))?