What is the Cartesian form of $(-17,(-3pi)/6))$ ?

Question

1614 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-15T01:38:07

$(0,17)$

To write a polar point into cartesian form, we convert it into the parametric form using these equations:

$x=rcostheta$
$y=rsintheta$

$r=-17$ and $theta=(-3pi)/6$ Plug into these equations:

$x=-17cos(-pi/2)=0$
$y=-17sin(-pi/2)=17$

So we have $x=0$ and $y=17$ . Write this as a point:

$(0,17)$

What is the Cartesian form of (-17,(-3pi)/6))(-17,(-3pi)/6))?