What is the Cartesian form of $(18, \frac{- 11 π}{8}))$ $(18,(-11pi)/8))$ ?

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What is the Cartesian form of $(18, \frac{- 11 π}{8}))$ $(18,(-11pi)/8))$ ?

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Answer 1 · 2016-03-04T10:50:39

(-6.888 , 16.63 )

Explanation:

Using the formulae that links Polar to Cartesian coordinates.

$∙ x = r cos θ$ $• x = rcostheta$

$∙ y = r sin θ$ $• y = rsintheta$

here r = 18 and $θ = \frac{- 11 π}{8}$ $theta = (-11pi)/8$

$x = 18 cos (\frac{- 11 π}{8}) \approx - 6.888$ $x = 18cos((-11pi)/8) ≈ -6.888$

$y = 18 sin (\frac{- 11 π}{8}) \approx 16.63$ $y = 18sin((-11pi)/8) ≈ 16.63$

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What is the Cartesian form of $(18, \frac{- 11 π}{8}))$ $(18,(-11pi)/8))$ ?

1 Answer

Explanation:

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What is the Cartesian form of (18,−11π8))(18,(-11pi)/8))?

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What is the Cartesian form of $(18, \frac{- 11 π}{8}))$ $(18,(-11pi)/8))$ ?