What is the Cartesian form of $(18, \frac{- 34 π}{8})$ $(18,(-34pi)/8)$ ?

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What is the Cartesian form of $(18, \frac{- 34 π}{8})$ $(18,(-34pi)/8)$ ?

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Answer 1 · 2016-11-16T15:51:30

The cartesian coordinates are $= (9 \sqrt{2}, - 9 \sqrt{2})$ $=(9sqrt2,-9sqrt2)$

Explanation:

We use the following equations to transform polar coordinates to cartesian coordinates.

$x = r cos θ$ $x=rcostheta$

$y = r sin θ$ $y=rsintheta$

The polar coordinates are $(18, \frac{- 34 π}{8})$ $(18,(-34pi)/8)$

therefore,

#x=18cos ((-34pi)/8)=18cos ((-2pi)/8)=18*cos(-pi/4)

$x = 18 \cdot \frac{\sqrt{2}}{2} = 9 \sqrt{2}$ $x=18*sqrt2/2=9sqrt2$

$y = 18 \cdot sin (\frac{- 34 π}{8}) = 18 \cdot sin (\frac{- 2 π}{8}) = 18 \cdot sin (- \frac{π}{4})$ $y=18*sin((-34pi)/8)=18*sin((-2pi)/8)=18*sin(-pi/4)$

$y = - 18 \cdot \frac{\sqrt{2}}{2} = - 9 \sqrt{2}$ $y=-18*sqrt2/2=-9sqrt2$

$(x, y) = (9 \sqrt{2}, - 9 \sqrt{2})$ $(x,y)=(9sqrt2,-9sqrt2)$

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What is the Cartesian form of $(18, \frac{- 34 π}{8})$ $(18,(-34pi)/8)$ ?

1 Answer

Explanation:

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Math

Humanities

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What is the Cartesian form of (18,−34π8)(18,(-34pi)/8)?

1 Answer

Explanation:

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What is the Cartesian form of $(18, \frac{- 34 π}{8})$ $(18,(-34pi)/8)$ ?