What is the Cartesian form of $(-2,(-11pi) /16)$ ?

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Answer 1 · 2018-06-11T05:30:02

Cartesian form $(-2*cos((-11pi)/16), -2*sin((-11pi)/16))=(1.111, 1.663)$

The given $(r, theta)=(-2, -(11pi)/16)$

using

$x=r*cos theta=-2*cos((-11pi)/16)=1.111$

$y=r*sin theta=-2*sin((-11pi)/16)=1.663$

and our Cartesian form $(x, y)=(1.111, 1.663)$

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I hope the explanation is useful....God bless..

What is the Cartesian form of (-2,(-11pi) /16)(-2,(-11pi) /16)?