What is the Cartesian form of $( -2 , (13pi)/3 )$ ?

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Answer 1 · 2016-01-09T05:05:35

$(-1, -sqrt(3))$

For the x:

$x=r cos theta$

$x=(-2)*cos (13 pi/3)= -1$

$x=-1$

For the y:

$y=r* sin theta$

$y=(-2)*sin (13 pi/3)=-sqrt(3)$

$y=-sqrt(3)$

the required answer is $(-1, -sqrt(3))$

What is the Cartesian form of ( -2 , (13pi)/3 ) ( -2 , (13pi)/3 ) ?