What is the Cartesian form of #( 2 , ( - 15pi)/2 ) #?

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Answer 1 · 2018-01-08T22:46:54

#( 0 , 2)#

For polar coordinates we have: #(r,theta)#

For Cartesian coordinates we have #(x,y)#

#x=rcos(theta)#

#y=rsin(theta)#

#x=2cos((-15pi)/2)=0#

#y=2sin((-15pi)/2)=2#

#:.#

Cartesian coordinates:

#( 0 , 2)#