What is the Cartesian form of $(-2,(-161pi) /16)$ ?

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Answer 1 · 2017-04-16T00:54:35

$(1.962,-.390)$

Use the parametric form to find the $x$ and $y$ components of this polar coordinate. Remember that:

$x=rcostheta$

$y=rsintheta$

Plug into these formulas:

$x=-2cos(-161pi/16)~~1.962$

$y=-2sin(-161pi/16)~~-.390$

We have our $x$ and $y$ component. Now write it as a coordinate:

$(1.962,-.390)$

What is the Cartesian form of (-2,(-161pi) /16)(-2,(-161pi) /16)?