What is the Cartesian form of $(-23,(5pi)/16))$ ?

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Answer 1 · 2017-04-08T20:33:26

(x,y)
( $23sqrt3/2$ , $-23/2$ )

Polar and cartesian points are related through:

$x=rcos(theta)$
$y=rsintheta$

$x=rcos(theta)$
$x=-23(cos((5pi)/6))$
$cos ((5pi)/6)= -sqrt(3)/2$

$-sqrt 3/2(-23)= 23sqrt3/2$
$x=23sqrt3/2$

$y=rsintheta$
$x=23sqrt3/2$

$sin((5pi)/6)=1/2$

$y=-23/2$

(x,y)
( $23sqrt3/2$ , $-23/2$ )

What is the Cartesian form of (-23,(5pi)/16))(-23,(5pi)/16))?