What is the Cartesian form of $(-24,(17pi)/6))$ ?

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Answer 1 · 2016-01-17T09:14:47

Cartesian Form $(12 sqrt(3), -12)$

Given Polar Form $(r, theta)$ = $(-24, 17 pi/6)$
Where $r=-24$ and $theta=(17 pi)/6$
$x=r *cos theta$
$x=-24*cos ((17 pi)/6)$

$x=-24*(-sqrt(3)/2)$

$x=12 sqrt(3)$

$y=r*sin theta$

$y=-24 *sin((17 pi)/6)$

$y= -24*(1/2)$
$y=-12$

therefore
$(x, y)=(12 sqrt(3), -12)$

What is the Cartesian form of (-24,(17pi)/6))(-24,(17pi)/6))?