What is the Cartesian form of $(-25,(-3pi)/4))$ ?

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Answer 1 · 2018-01-20T16:26:23

The cartesian form is $( (25sqrt(2))/2, (25sqrt(2))/2 )$ .

We can use $x=rcos(theta)$ and $y=rsin(theta)$ to convert:

$x=-25cos(-(3pi)/4)=-25(-sqrt(2)/2)=(25sqrt(2))/2$
$y=-25sin(-(3pi)/4)=-25(-sqrt(2)/2)=(25sqrt(2))/2$

So the cartesian form is $( (25sqrt(2))/2, (25sqrt(2))/2 )$ .

What is the Cartesian form of (-25,(-3pi)/4))(-25,(-3pi)/4))?