What is the Cartesian form of $( -3 , (25pi)/12 )$ ?

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Answer 1 · 2018-07-27T13:00:45

$(0,-3)$

![ jwilson.coe.uga.edu )

$x=rcostheta = -3cos((25pi)/2)=-3cos(pi/2 + 12pi)$

$=-3cos(pi/2)=0$

$y=rsintheta=-3sin((25pi)/2) = -3sin(pi/2+12pi)$

$=-3sin(pi/2) = -3$

Hence the Cartesian form of $(-3, (25pi)/12)$ is $(0,-3)$ .

What is the Cartesian form of ( -3 , (25pi)/12 ) ( -3 , (25pi)/12 ) ?