What is the Cartesian form of $(33,(-pi)/8)$ ?

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Answer 1 · 2018-05-03T11:37:09

$((33sqrt(2+sqrt2))/2,(33sqrt(2-sqrt2))/2)~~(30.5,-12,6)$

$(r,theta)->(x,y);(x,y)-=(rcostheta,rsintheta)$

$r=33$
$theta=-pi/8$

$(x,y)=(33cos(-pi/8),33sin(-pi/8))=((33sqrt(2+sqrt2))/2,(33sqrt(2-sqrt2))/2)~~(30.5,-12,6)$

What is the Cartesian form of (33,(-pi)/8)(33,(-pi)/8)?