What is the Cartesian form of $(-64,(17pi)/12)$ ?

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Answer 1 · 2017-11-08T18:04:14

$( 16.56 , 61.82 )$

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It can be seen from the diagram that the x coordinate of P is $rcos(theta)$ and the y coordinate of P is $rsin(theta)$

So:

$x=rcos(theta)$

$y=rsin(theta)$

From example:

$x=-64cos((17pi)/12)= 16.56$

$y=-64sin((17pi)/12)=61.82$

Cartesian coordinate:

$( 16.56 , 61.82 )$

What is the Cartesian form of (-64,(17pi)/12)(-64,(17pi)/12)?