What is the Cartesian form of $(-7,(11pi)/8)$ ?

Question

1384 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-20T12:49:17

Cartesian form of coordinates are $(2.6789,6.4673)$

Cartesian form of $(r,theta)$ is $(rcostheta,rsintheta)$

Hence for $(-7, 11pi/8)$ , it will be

$(-7cos(11pi/8), -7sin(11pi/8))$

As $cos(11pi/8)=-0.3827$ and $sin(11pi/8)=-0.9239$

Hence cartesian form of coordinates are $(2.6789,6.4673)$

What is the Cartesian form of (-7,(11pi)/8)(-7,(11pi)/8)?