What is the Cartesian form of $(- 7, \frac{- 35 π}{12})$ $( -7 , (-35pi)/12 )$ , where the original coordinates are in polar?

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Answer 1 · 2017-05-27T00:06:08

The point is: $(6.76, 1.81)$ $(6.76,1.81)$

To convert to Cartesian, use the equations:

x = $r cos (θ)$ $rcos(theta)$ and $y = r sin (θ)$ $y = rsin(theta)$

We are given: $r = - 7$ $r = -7$ and $θ = \frac{- 35 π}{12}$ $theta = (-35pi)/12$

x = $- 7 cos (\frac{- 35 π}{12})$ $-7cos((-35pi)/12)$ and $y = - 7 sin (\frac{- 35 π}{12})$ $y = -7sin((-35pi)/12)$

$x \approx 6.76$ $x ~~ 6.76$ and $y \approx 1.81$ $y ~~ 1.81$

What is the Cartesian form of ( -7 , (-35pi)/12 ) (−7,−35π12)( -7 , (-35pi)/12 ) , where the original coordinates are in polar?