What is the Cartesian form of $( -8, (-7pi)/3 )$ ?

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Answer 1 · 2017-06-11T03:59:31

$(-8,-7pi/3) to (-4, 4sqrt3)$

The conversion is $(r,theta) to (rcos(theta),rsin(theta))$

$(-8,-7pi/3) to (-8cos((-7pi)/3), -8sin((-7pi/3)))$

$(-8,-7pi/3) to (-8(0.5), -8(-sqrt3/2))$

$(-8,-7pi/3) to (-4, 4sqrt3)$

What is the Cartesian form of ( -8, (-7pi)/3 ) ( -8, (-7pi)/3 ) ?