What is the Cartesian form of $(81,(24pi)/12)$ ?

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Answer 1 · 2018-01-16T18:26:46

$(81,0)$

polar form: $(r, theta)$
cartesian form: $(x,y)$

$x = r cos theta$
$y = r sin theta$

here, $r = 81, theta = (24pi)/12$
$theta = 2pi$

$r cos theta = 81 cos 2pi$

$= 81 * 1$

$= 81$

$r sin theta = 81 sin 2pi$

$= 81 * 0$

$= 0$

$x = 81, y = 0$

cartesian coordinates: $(81, 0)$

What is the Cartesian form of (81,(24pi)/12)(81,(24pi)/12)?