What is the Cartesian form of $(- 9, \frac{3 π}{4})$ $(-9,(3pi )/4)$ ?

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Answer 1 · 2016-12-23T07:12:59

The answer is $= (9 \frac{\sqrt{2}}{2}, - 9 \frac{\sqrt{2}}{2})$ $=(9sqrt2/2,-9sqrt2/2)$

We apply the equations to go from polar coordinates $(r, θ)$ $(r,theta)$ to cartesian coordinates $(x, y)$ $(x,y)$

$x = r cos θ$ $x=rcostheta$

$y = r sin θ$ $y=rsintheta$

Therefore,

$x = - 9 \cdot cos (\frac{3 π}{4}) = - 9 \cdot - \frac{\sqrt{2}}{2} = 9 \frac{\sqrt{2}}{2}$ $x=-9*cos((3pi)/4)=-9*-sqrt2/2=9sqrt2/2$

$y = - 9 sin (\frac{3 π}{4}) = - 9 \cdot \frac{\sqrt{2}}{2} = - 9 \frac{\sqrt{2}}{2}$ $y=-9sin((3pi)/4)=-9*sqrt2/2=-9sqrt2/2$

What is the Cartesian form of (-9,(3pi )/4)(−9,3π4)(-9,(3pi )/4)?