What is the circumference of the circle whose equation is $(x-9)^2+(y-3)^2=64$ ?

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Answer 1 · 2018-04-12T08:41:19

The circumference of circle $(x-9)^2+(y-3)^2=64$ is $16pi$ .

Equation of a circle with center $(h,k)$ and radius $r$ is

$(x-h)^2+(y-k)^2=r^2$

Hence $(x-9)^2+(y-3)^2=64=8^2$ is a circle

with center $(9,3)$ and radius $8$

As circumference of circle of radius $r$ is $2pir$

the circumference of circle $(x-9)^2+(y-3)^2=64$ is $2xxpixx8=16pi$

What is the circumference of the circle whose equation is (x-9)^2+(y-3)^2=64(x-9)^2+(y-3)^2=64?