What is the cross product of (300i+200j150k) and (i+j7k)?

1 Answer
May 5, 2016

=1250ˆi2250ˆj500ˆk

Explanation:

(300ˆi+200ˆj150ˆk)×(ˆi+ˆj7ˆk)
=(200(7)1(150))ˆi+((150)1(7)(300))ˆj+((3001)(1200))ˆk)
=1250ˆi2250ˆj500ˆk