What is the cross product of #<7, 5 ,6 ># and #<3 ,5 ,-2 >#?

1 Answer

The cross product of given coordinates is
#-4(10hati-8hatj-5hatk)#.

Explanation:

Let us consider #vecA=(7, 5, 6), vecB=(3, 5, -2)# as #vecA= 7hati+5hatj+6hatk#, #vecB=3hati+5hatj-2hatk#
#vecAxxvecB = hati(-10-30)-hatj(-14-18)+hatk(35-15)#
#=> -40hati+32hatj+20hatk#
#:. vecAxxvecB = -4(10hati-8hatj-5hatk)#.