What is the cube root of $40 a^5 b^7$ simplified?

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Answer 1 · 2015-09-25T23:37:29

It is $root(3) (40 a^5 b^7)=root(3) (2^3*5*a^3*a^2*b^6*b)=2*a*b^2*(root(3) (5*a^2*b) )$

What is the cube root of 40 a^5 b^740 a^5 b^7 simplified?