What is the derivative of $f (x) = {log}_{b} (g (x))$ $f(x)=log_b(g(x))$ ?

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Answer 1 · 2014-09-01T23:02:37

By using Chain Rule with $(log_bx)'=1/{(lnb)x}$ , we have
$f'(x)=1/{(lnb)g(x)}cdot g'(x)={g'(x)}/{(lnb)g(x)}$ .

What is the derivative of f(x)=log_b(g(x))f(x)=logb(g(x))f(x)=log_b(g(x)) ?