What is the derivative of f(x)= x^(4/5) (x-5)^2?

1 Answer
May 6, 2018

f'(x)=14/5x^(9/5)-18x^(4/5)+20x^(-1/5)

Explanation:

"differentiate using the "color(blue)"power rule"

•color(white)(x)d/dx(ax^n)=nax^(n-1)

"expand and distribute"

f(x)=x^(4/5)(x^2-10x+25)

color(white)(f(x))=x^(14/5)-10x^(9/5)+25x^(4/5)

rArrf'(x)=14/5x^(9/5)-18x^(4/5)+20x^(-1/5)