What is the derivative of this function #sin(x) / (1 + sin^2(x))#? Calculus Differentiating Trigonometric Functions Intuitive Approach to the derivative of y=sin(x) 1 Answer Gerardina C. Jan 19, 2017 #cos^3x/(1+sin^2x)^2# Explanation: You would use the division rule: #f'(x)=(cosx(1+sin^2x)-sinx(2sinxcosx))/(1+sin^2x)^2# #=(cosxcolor(red)(+cosxsin^2x-2sin^2xcosx))/(1+sin^2x)^2##->#sum like terms #=(color(red)cosx-sin^2xcolor(red)cosx)/(1+sin^2x)^2# #->#factorize #=(cosx(color(red)(1-sin^2x)))/(1+sin^2x)^2##->#substitute #=(cosxcolor(red)(cos^2x))/(1+sin^2x)^2##->#multiply #=cos^3x/(1+sin^2x)^2# Answer link Related questions What is the derivative of #-sin(x)#? What is the derivative of #sin(2x)#? How do I find the derivative of #y=sin(2x) - 2sin(x)#? How do you find the second derivative of #y=2sin3x-5sin6x#? How do you compute #d/dx 3sinh(3/x)#? How do you find the derivative #y=xsinx + cosx#? What is the derivative of #sin(x^2y^2)#? What is #f'(-pi/3)# when you are given #f(x)=sin^7(x)#? How do you find the fist and second derivative of #pi*sin(pix)#? If f(x)= 2x sin(x) cos(x), how do you find f'(x)? See all questions in Intuitive Approach to the derivative of y=sin(x) Impact of this question 1396 views around the world You can reuse this answer Creative Commons License