What is the derivative of # x^2 x e^-x#? Calculus Basic Differentiation Rules Product Rule 1 Answer Nam D. May 25, 2018 #3x^2e^-x-x^3e^-x# Explanation: Given: #x^2xe^-x#. #=x^3e^-x# We use the product rule, which states that, #d/dx(xy)=yd/dx(x)+xd/dx(y)# #:.dy/dx(x^3e^-x)=e^-xd/dx(x^3)+x^3d/dx(e^-x)# #=e^-x*3x^2+x^3*-e^-x# #=3x^2e^-x-x^3e^-x# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 1429 views around the world You can reuse this answer Creative Commons License