What is the derivative of (x^3 + 2)^2(x^5 + 4)^4?

1 Answer
Jun 29, 2018

f^'(x) =2 x^2(x^3+2)(x^5+4)^3 ( 13 x ^5+20 x^2+12)

Explanation:

f(x) = (x^3+2)^2 (x^5+4)^4

Product rule : d/d x (f g)= f g^'+g f^'

f^'(x) = (x^3+2)^2 * 4 (x^5+4)^3 * (5 x^4) +(x^5+4)^4 * 2(x^3+2)*(3 x^2)

f^'(x) =2 x^2(x^3+2)(x^5+4)^3 {( 10 x^5+20x^2)+(3 x^5+12)}

f^'(x) =2 x^2(x^3+2)(x^5+4)^3 ( 13 x ^5+20 x^2+12) [Ans]