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What is the derivative of $y = (\sqrt{x}) (x - 1)$ $y=(sqrt(x))(x-1)$ ?

1 Answer

Jan 11, 2017

$\frac{x - 1}{2 \sqrt{x}} + \sqrt{x}$ $(x-1)/(2sqrtx) +sqrtx$

Explanation:

Applying product rule y'= $(x - 1) \frac{d}{d x} \sqrt{x} + \sqrt{x} \frac{d}{d x} (x - 1)$ $(x-1) d/dx sqrtx + sqrt x d/dx (x-1)$

= $\frac{x - 1}{2 \sqrt{x}} + \sqrt{x}$ $(x-1)/(2sqrtx) +sqrtx$

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