What is the distance between polar coordinates (-2, 300^circ) and (2, 10^circ)?

1 Answer
Jul 9, 2018

color(indigo)("Distance " d ~~ 3.2766

Explanation:

https://www.aplustopper.com/stewart-calculus-7e-solutions-chapter-10-parametric-equations-polar-coordinates-exercise-10-3/https://www.aplustopper.com/stewart-calculus-7e-solutions-chapter-10-parametric-equations-polar-coordinates-exercise-10-3/

d = sqrt (r_1^2 + r_2 ^2 - 2 r_1 r_2 cos (theta_1 - theta_2))

(r_1, theta_1) = (-2, 300^@), (r_2, theta_2) = (2, 10^@)

d = sqrt(-2^2 + 2^2 - 2 * -2 * 2 * cos (300-10)

d = sqrt (8 + 8 cos 290) ~~ 3.2766