What is the domain and range for f(x)=sqrt(x-1)?

1 Answer
May 10, 2018

" "
color(blue)("Domain: " x>=1, Interval Notation: color(brown)([1, oo)

color(blue)("Range: " f(x)>=0, Interval Notation: color(brown)([0, oo)

Explanation:

" "
color(green)"Step 1:"

**Domain: **

The domain of the given function f(x) is the set of input values for which f(x) is real and defined.

Point to note:

color(red)(sqrt(f(x)) = f(x)>=0

Solve for (x-1)>=0 to obtain x>=1.

Hence,

color(blue)("Domain: " x>=1

Interval Notation: color(brown)([1, oo)

color(green)"Step 2:"

**Range: **

Range is the set of values of the dependent variable used in the function f(x) for which f(x) is defined.

Hence,

color(blue)("Range: " f(x)>=0

Interval Notation: color(brown)([0, oo)

color(green)"Step 3:"

Additional note:

The function y = f(x)= sqrt(x-1) has no asymptotes.

Create a data table using values for x and corresponding values for y:

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Observe that Zero and "Negative values" of x make the function f(x) "undefined" at those points.

Graph f(x) = sqrt(x-1 to verify the results obtained:

enter image source here