What is the domain and range of $d (s) = 0.009 s^{2}$ $d(s)= 0.009s^2$ ?

Question

What is the domain and range of $d (s) = 0.009 s^{2}$ $d(s)= 0.009s^2$ ?

1 Answer

Impact of this question

1392 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-24T12:40:29

There is no restriction on the domain (no radicals or fractions)

Explanation:

So domain $= (- \infty, + \infty)$ $=(-oo,+oo)$

Since $d (s)$ $d(s)$ is a square and therefore never negative, the range is restricted to non-negative numbers, the smallest being $d (0) = 0$ $d(0)=0$

So range $= (0, + \infty)$ $=(0,+oo)$

Science

Math

Humanities

... and beyond

What is the domain and range of $d (s) = 0.009 s^{2}$ $d(s)= 0.009s^2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the domain and range of d(s)= 0.009s^2d(s)=0.009s2d(s)= 0.009s^2?

1 Answer

Explanation:

Related questions

Impact of this question

What is the domain and range of $d (s) = 0.009 s^{2}$ $d(s)= 0.009s^2$ ?