What is the domain and range of $f (t) = \sqrt{9 - t}$ $f(t) = sqrt(9-t)$ ?

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Answer 1 · 2015-10-13T02:44:40

${t:RR, t<=9}$ 0r $(-oo,9]$

The domain of f(t) would be such that $9>=t$ that means t should be less than or equal to 9. This can be expressed as

${t:RR, t<=9}$ or $(-oo,9]$

What is the domain and range of f(t) = sqrt(9-t)f(t)=√9−tf(t) = sqrt(9-t)?