What is the domain and range of y = - sqrt(9-x^2)?

1 Answer
Aug 21, 2015

Domain: [-3, 3]
Range: [-3, 0]

Explanation:

In order to find the function's domain, you need to take into account the fact that, for real numbers, you can only take the square root of a positive number.

In other words, in oerder for the function to be defined, you need the expression that's under the square root to be positive.

9 - x^2 >= 0

x^2 <= 9 implies |x| <= 3

This means that you have

x >= -3" " and " "x<=3

For any value of x outside the interval [-3, 3], the expression under the square root will be negative, which means that the function will be undefined. Therefore, the domain of the function will be x in [-3, 3].

Now for the range. For any value of x in [-3, 3], the function will be negative.

The maximum value the expression under the radical can take is for x=0

9 - 0^2 = 9

which means that the minimum value of the function will be

y = -sqrt(9)= -3

Therefore, the range of the function will be [-3, 0].

graph{-sqrt(9-x^2) [-10, 10, -5, 5]}