What is the domain and range of y= sqrt(x) -2?

1 Answer
Jan 23, 2017

"Domain="RR^=uu{0}=[0,oo).

"Range="[-2,oo).

Explanation:

We will restrict our discussion in RR.

As we can not find the square root of x<0, x>=0

So, the Domain is the set of all non-negative reals, i.e.,

RR^+uu{0}=[0,oo).

Also, AA x in RR^+uu{0}, sqrtx>=0 rArr y=sqrtx-2>=-2.

Hence, the Range is [-2,oo).

Enjoy maths.!