What is the domain of $\frac{2 x^{2} + x - 1}{x^{3} - 9 x}$ $(2x^2+x-1)/(x^3-9x)$ ?

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Answer 1 · 2015-09-08T23:08:15

The domain is all the real values except those who nullify $x^{3} - 9 x$ $x^3-9x$

So we have $x^{3} - 9 x = 0 \Rightarrow x (x^{2} - 9) = 0 \Rightarrow x = 0, x = 3, x = - 3$ $x^3-9x=0=>x(x^2-9)=0=>x=0,x=3,x=-3$

So the domain is $R - {0, - 3, 3}$ $R-{0,-3,3}$ where R is the set of real numbers

What is the domain of (2x^2+x-1)/(x^3-9x)2x2+x−1x3−9x(2x^2+x-1)/(x^3-9x)?