What is the domain of f(x)=17x?

1 Answer
Apr 6, 2018

Domain: [17,)

Explanation:

One cannot have a negative under a square root, so we know 17x0. Adding x to both sides yields 17x. Thus, x can be any number greater than or equal to 17. This gives the interval [17,) as our domain.

To elaborate, n asks, "what number, when squared, gives n". Notice that positive numbers, when squared, give positive numbers. (22=4) Also, negative numbers, when squared, give positive numbers. (22=(2)(2)=4) So it follows that one cannot take the square root of a negative number, since no number, when squared, yields another negative number.

When we realize that, we know that 17x must be non-negative. This is written as the inequality 17x0. Algebraic manipulation gives 17x, and from this we extrapolate our interval [17,].