What is the domain of $f (x) = \sqrt{x + 1}$ $f(x)=sqrt(x+1)$ ?

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Answer 1 · 2016-11-15T14:40:23

The domain is $x \in [- 1, + \infty [$ $x in[-1, +oo[$

For a square root, the doman is $\geq 0$ $>=0$

Therefore, $x + 1 \geq 0$ $x+1>=0$

$\Rightarrow$ $=>$ $x \geq - 1$ $x>=-1$

Therefore the domain is $x \in [- 1, + \infty [$ $x in[-1, +oo[$

What is the domain of f(x)=√x+1f(x)=sqrt(x+1)?