What is the domain of $f (x) = {\frac{x - 1}{x + 4}}$ $f(x) = {(x - 1)/(x + 4)}$ ?

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Answer 1 · 2015-04-15T11:51:05

$f (x) = (\frac{x - 1}{x + 4})$ $f(x)=((x-1)/(x+4))$
has a domain of all values for which $f (x)$ $f(x)$ is defined.

$f (x)$ $f(x)$ is defined for all values of $x$ $x$ except the value that would cause the denominator to be $= 0$ $=0$

That is
the domain of $f (x)$ $f(x)$
are all values except $(- 4)$ $(-4)$

In set notation
Domain of $f (x) = (- \infty, - 4) \cup (- 4, + \infty)$ $f(x) = (-oo,-4)uu(-4,+oo)$

What is the domain of f(x) = {(x - 1)/(x + 4)}f(x)={x−1x+4}f(x) = {(x - 1)/(x + 4)}?