Question

What is the domain of `h(x)=sqrt(2x+1)`?

Answer 1

`x inRR,x>=-1/2`

Explanation:

`"we require "2x+1>=0`

`rArr2x>=-1rArrx>=-1/2`

`"domain is "x inRR,x>=-1/2`

`[-1/2,+oo)larrcolor(blue)"in interval notation"`
graph{sqrt(2x+1) [-10, 10, -5, 5]}