What is the domain of h(x)=sqrt(x-2)h(x)=x2?

1 Answer
Jun 17, 2018

x in [2, infty)x[2,)

Explanation:

For radical functions, we cannot have a quantity less than 00 inside the square root.

In this case, we know that h(2) = 0h(2)=0, but if xx is decreased any more than this, the radical will be undefined.

So we know that x = 2x=2 is the minimum value of the domain. As we increase xx, we have no issues as the radical always contains a positive number. So x -> inftyx.

So the domain would be all values of x >= 2x2, or

x in [2, infty)x[2,)