What is the domain of the function: $f (x) = \sqrt{4 x + 1}$ $f(x) = sqrt(4x+1)$ ?

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Answer 1 · 2015-09-13T21:51:03

It should be $4 x + 1 \geq 0 \Rightarrow x \geq - \frac{1}{4}$ $4x+1>=0=>x>=-1/4$ hence the domain is

$D (f) = [- \frac{1}{4}, + \infty)$ $D(f)=[-1/4,+oo)$

What is the domain of the function: f(x)=√4x+1f(x) = sqrt(4x+1) ?