What is the domain of the function: $f(x) =sqrt(x^2 - 2x + 5)$ ?

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Answer 1 · 2015-09-17T12:31:34

$D_f=R$

$x^2-2x+5>=0$

$D=b^2-4ac=(-2)^2-4*1*5=4-20=-16$

Because $D<0$ and $a=1>0$ , expression $x^2-2x+5>0$ for $AAx in R$ and square root can be calculated. Hence,

$D_f=R$

What is the domain of the function: f(x) =sqrt(x^2 - 2x + 5)f(x) =sqrt(x^2 - 2x + 5)?