What is the electron configuration of the gallium ion?

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What is the electron configuration of the gallium ion?

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Answer 1 · 2016-06-08T04:48:03

The electron configuration for Gallium, Ga is
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{1}$ $1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^1$

Explanation:

Gallium, Ga has 31 protons and 31 electrons. The superscripts represent the electrons present in each region of the periodic table.
The sum of these superscripts should equal the atomic number for a neutral atom. The last electron is in the 4th period, in the p region and the first electron in that region.

Answer 2 · 2016-07-05T23:43:42

The most common electron configuration for the gallium ion, ${Ga}^{3 +}$ $"Ga"^(3+)$ is
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10}$ $1s^2 2s^2 2p^6 3s^2 3p^6 3d^10$ or $[Ar] 3 d^{10}$ $["Ar"] 3d^10$ .

Explanation:

Gallium is in Group 13. It has 31 electrons.

Its electron configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p$ $1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p$

We form cations by removing electrons first from the outermost $p$ $p$ orbitals, followed by the $s$ $s$ orbital and finally the $d$ $d$ orbitals (if any more electrons need to be removed).

The options for $Ga$ $"Ga"$ would be to remove

the $4 p$ $4p$ electron and form ${Ga}^{+}$ $"Ga"^+$
the $4 p$ $4p$ electron and both $4 s$ $4s$ electrons and form ${Ga}^{3 +}$ $"Ga"^(3+)$ .

By far the most common ion of Group 13 metals is +3.

So. the most common gallium ion is ${Ga}^{3 +}$ $"Ga"^(3+)$ , and its electron configuration is $[Ar] 3 d^{10}$ $["Ar"] 3d^10$ .

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What is the electron configuration of the gallium ion?

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