What is the electron configuration of "Ti"^(2+)?

1 Answer
Jun 27, 2016

"Ti"^(2+): ["Ar"]3d^2

Explanation:

A good place to start when trying to figure out the electron configuration of an ion is the electron configuration of the neutral parent atom.

In this case, titanium, "Ti", is located in period 4, group 4 of the periodic table and has an atomic number of 22.

This means that a neutral titanium atom will contain 22 protons in its nucleus and 22 electrons surrounding its nucleus.

Therefore, the electron configuration of a neutral titanium atom must account for 22 electrons. Consequently, the electron configuration of the titanium(II) cation, "Ti"^(2+), must account for 20 electrons, since this cation is formed when a neutral titanium atom loses 2 electrons.

The electron configuration of a neutral titanium atom looks like this

"Ti: " 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2

Now, it's important to keep in mind that this notation for the electron configuration is useful when adding electrons to build an atom "from scratch" because in that case, the 4s orbital is filled before the 3d orbitals.

That happens because the empty 3d orbitals are actually higher in energy than the empty 4s orbital, as seen here

![www.chemguide.co.uk)

However, once the 4s orbital is filled, it becomes higher in energy than the 3d orbitals. This means that when titanium loses electrons, it does so from the 4s orbital first.

"Ti: " 1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4s^2

Therefore, the two electrons that are lost when the "Ti"^(2+) is formed will come from the 4s orbital, which means that the electron configuration of the cation is

color(green)(|bar(ul(color(white)(a/a)color(black)("Ti"^(2+): 1s^2 2s^2 2p^6 3s^2 3p^6 3d^2)color(white)(a/a)|)))

If you want, you can use the noble gas shorthand notation to write

color(green)(|bar(ul(color(white)(a/a)color(black)("Ti"^(2+): ["Ar"] 3d^2)color(white)(a/a)|)))

Here ["Ar"] represents the electron configuration of argon, the noble gas that comes immediately before titanium in the periodic table.