What is the equation of a circle with a radius of 5?

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Answer 1 · 2014-09-13T04:56:31

If the equation is in standard form it would look like ...

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x-h)^2+(y-k)^2=r^2$

$(h, k)$ $(h,k)$ is the center of the circle

To answer the question the equation of a circle with a radius of 5 would look like either of the following ...

${(x - h)}^{2} + {(y - k)}^{2} = 5^{2}$ $(x-h)^2+(y-k)^2=5^2$

or

${(x - h)}^{2} + {(y - k)}^{2} = 25$ $(x-h)^2+(y-k)^2=25$