Question

What is the equation of the line between `(1,3)` and `(-4,1)`?

Answer 1

Its equation is ; `5y = 2x + 13`

Explanation:

first you will find its gradient ( slope );

gradient = `(y_1 - y_2)/(x_1-x_2)` or `(y_2 - y_1)/(x_2-x_1)`

{I am applying the first one]

gradient =`( 3-1)/(1-(-4))`

gradient = `2/5`

now put gradient , in this equation

y = m*x + c

{where m is gradient & c is y-intercept (where x is 0) }

`y = (2/5)*x + c`

{now put the value of y and x, either use first point or the second one i.e. (1, 3) or (-4, 1) }

`3 = (2/5)* 1 +c`
`3-(2/5) = c`
`13/5 = c`

{c is found now put m and c in the equation y = mx + c}

`y = (2/5)*x + 13/5`

`5 y= 2x + 13`

{you can put any two points and the answer will be the same}

equation found...!