What is the equation of the line between $(10,3)$ and $(-4,12)$ ?

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Answer 1 · 2018-04-10T14:13:40

$9x+14y-132=0$

The equation of a line is given by $y-y_1=m(x-x_1)$ where $m=(y_2-y_1)/(x_2-x_1)$ .

The gradient: $m=(12-3)/(-4-10)=9/-14$

The equation of the line is: $y-3=-9/14(x-10)$

$14y-42=-9x+90$ multiply both sides by $14$ and expand brackets

$9x+14y-132=0$

What is the equation of the line between (10,3)(10,3) and (-4,12)(-4,12)?