What is the equation of the line between $(-18,14)$ and $(19,24)$ ?

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Answer 1 · 2016-02-25T03:56:13

$y = 10/37x - 806/37$
or
$37y = 10x - 806$

The formula for slope is $m =(y_2 - y_1)/(x_2-x_1)$

For the points (-18,14) and (19,24) where
$x_1 = -18$
$y_1 =14$
$x_2 = 19$
$y_2 = 24$

$m =(y_2 - y_1)/(x_2-x_1)$

$m =(24 - 14)/(19-(-18)$

$m = 10/37$

To determine the equation of the line we can use the point slope formula and plug in the values given in the question.

$(y - y_1) = m(x - x_1)$

$m = 10/37$
$x_1 = -18$
$y_1 = 14$

$(y - (-18)) = 10/37$ (x - 14)#

$y + 18 = 10/37x - 140/37$

$y + 18 - 18 = 10/37x - 140/37 - 18$

$y = 10/37x - 140/37 - 666/37$

$y = 10/37x - 806/37$

$(y = 10/37x - 806/37) x 37$

$37y = 10x - 806$

What is the equation of the line between (-18,14)(-18,14) and (19,24)(19,24)?